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9k^2+50k-24=0
a = 9; b = 50; c = -24;
Δ = b2-4ac
Δ = 502-4·9·(-24)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-58}{2*9}=\frac{-108}{18} =-6 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+58}{2*9}=\frac{8}{18} =4/9 $
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